But, under drastic conditions it gives $\mathrm{N}_{2} \mathrm{O}_{3}$ and $\mathrm{HF}$ via series of reactions involving 3 times $\mathrm{S}_{\mathrm{N}_{1}}$ with deprotonation and then 2 times dehydration.
$(I)$ $H_5P_3O_{10}$ $(II)$ $H_6 P_4O_{13}$
$(III)$ $H_5P_5O_{15}$ $(IV)$ $H_7P_5O_{16}$
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