$(I)\,\begin{array}{*{20}{c}}
{C{H_3}CHC{H_2}C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,} \\
{Cl\,\,\,\,\,\,\,\,\,}
\end{array}$
$(II)\,CH_3CH_2CH_2Cl$
$(III)\,H_3CO-C_6H_4-CH_2Cl$
\(\mathrm{R}-\mathrm{X} \rightleftharpoons \mathrm{R}^{+}+\mathrm{X}^{-}\)
In the second step, the intermediate alkyl cation reacts rapidly with water to produce alcohol.
\(\mathrm{R}^{+}+\mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{ROH}\)
Hence, the order of reactivity of halides for the \(\mathrm{S}_{\mathrm{N}} 1\) mechanism is \(\mathrm{II}<\mathrm{I}<\mathrm{III}\).
ઉપરોક્ત પ્રકિયા માં નીપજ $(B)$ અને $(D) $ શું હશે ?