MCQ
$SnCl_2$ acts as a reducing agent
- A$SnCl_2$ can accept electrons readily
- B$Sn^{2+}$ is more stable than $Sn^{4+}$
- ✓$Sn^{4+}$ is more stable than $Sn^{2+}$
- D$Sn^{2+}$ can be easily converted to metallic tin
✓
Answer
Correct option: C.
$Sn^{4+}$ is more stable than $Sn^{2+}$
c
$\mathrm{SnCl}_{2}$ acts as a reducing agent because there is high tendency of $\operatorname{Sn}(\mathrm{II})$ ions to convert into $\mathrm{Sn}(\mathrm{IV})$ as $\mathrm{Sn}^{4+}$ is more stable than $\mathrm{Sn}^{2+}$
$\mathrm{SnCl}_{2}$ acts as a reducing agent because there is high tendency of $\operatorname{Sn}(\mathrm{II})$ ions to convert into $\mathrm{Sn}(\mathrm{IV})$ as $\mathrm{Sn}^{4+}$ is more stable than $\mathrm{Sn}^{2+}$
Hence, option $\mathrm{C}$ is the correct answer.
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