MCQ
$S{O_2}$ acts as temporary bleaching agent but $C{l_2}$ acts as permanent bleaching agent. Why
- A$C{l_2}$ bleaches due to reduction but $S{O_2}$ due to oxidation
- ✓$C{l_2}$ bleaches due to reduction but $S{O_2}$ due to reduction
- CBoth of these
- DNone of these
