MCQ
Sodium hydroxide solution reacts with phosphorus to give phosphine. To bring about this reaction, we need
- ✓White phosphorus and dil. $NaOH$
- BWhite phosphorus and conc. $NaOH$
- CRed phosphorus and dil. $NaOH$
- DRed phosphorus and conc. $NaOH$
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$\begin{array}{*{20}{c}} {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,OH} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\ {( \pm )\,\,C{H_3} - C{H_2} - CH - C{H_3}} \end{array}$ $\xrightarrow[\Delta ]{{{H_3}P{O_4}}}P\,\xrightarrow[{Ni}]{{{D_2}}}Q$
$A + O_2 \to B$ ;
$B + O_2 + H_2O \to C$
$A, B$ and $C$ are