[આણ્વિય દળ $: {Na}=23.0, {O}=16.0, {H}=1.0]$
\(\frac{20}{62} {moles}\)
Moles of \({NaOH}\) formed \(=\frac{20}{62} \times 2\)
\([{NaOH}]=\frac{\frac{40}{62}}{\frac{500}{1000}}=1.29\, {M}=13 \times 10^{-1} \,{M}\)
(Nearest integer)
[આણ્વિય દળ : ${H}: 1.0, {C}: 12.0, {O}: 16.0]$
[આણ્વિય દળ $: {Na}=23.0, {O}=16.0, {H}=1.0]$