Download App

STD 11 - 6.2. Equilibrium - II (icon Equilibrium) — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - 6.2. Equilibrium - II (icon Equilibrium)4 Marks
MCQ
Solid $Ba(NO_3)_2$ is gradually dissolved in $1\times10^{-4}\, M\, Na_2CO_3$ solution. At what concentration of $Ba^{+2}$ the precipitation of $BaCO_3$ will start? (If $K_{sp}$ of $BaCO_3 = 5.1\times10^{-9}$)
  • A
    $4.1\times10^{-5}\, M$
  • ✓
    $5.1\times10^{-5}\, M$
  • C
    $1.6\times10^{-4}\, M$
  • D
    $8.1\times10^{-7}\, M$
✓

Answer

Correct option: B.
$5.1\times10^{-5}\, M$
b
$\left[\mathrm{Ba}^{+2}\right]\left(10^{-4}\right)=5.1 \times 10^{-9}$

$\boxed{\left[ {{\text{B}}{{\text{a}}^{ + 2}}} \right] = 5.1 \times {{10}^{ - 5}}{\mkern 1mu} {\text{M}}}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

JEE STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

Major products of following reactions are related as :
→
Identify product $(P)$
→
The shape of ethylene molecule is
→
A solution is $500\, ml$ of $2\, M \,KOH$ is added to $500\, ml$ of $2\, M \,HCl$ and the mixture is well shaken.The rise in temperature $T_1$ is noted. The experiment is then repeated using $250\, ml$ of each solution and rise in temperature $T_2$ is again noted. Assume all heat is taken by the solution
→
$2\ mol$ of $\ce{FeSO_4}$ are oxidised by $'X\ '\ mol$ of $\ce{KMnO_4}$ whereas $2\ mol$ of  $\ce{FeC_2O_4}$ are oxidised by $'Y\ '\ mol$ of $\ce{KMnO_4}$. The ratio of $X$ and $Y$ is
→
$STATEMENT-1$: The geometrical isomers of the complex $\left[\mathrm{M}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right]$ are optically inactive. and

$STATEMENT-2$: Both geometrical isomers of the complex $\left[\mathrm{M}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right]$ possess axis of symmetry.

→
Relation between rate constant and temperature by Arrhenius equation is
→
The major product $(P)$ in the following reaction is :
→
Which one of the following substituents at para position is most effective in stabilizing the phenoxide ion ?
→
Which statement is correct for product $‘X’$ ?

$\begin{array}{*{20}{c}}
  {O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C \equiv CH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O\,\,\,} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {Cl - C - C{H_2} - C - C{H_2} - C{H_2} - C - C{H_3}} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_2}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C \equiv N\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
\end{array}$ $\xrightarrow[{BaS{O_4}}]{{{H_2}/Pd}}\,'X'$

→