$\therefore \,[CO_3^ - ] = 1.0 \times {10^{ - 4}}\,M$
$i.e.\,\,\,s = 1.0 \times {10^{ - 4}}\,M$
At equilibrium
$[B{a^{ + + }}][CO_3^ - ] = {K_{sp}}\,of\,BaC{O_3}$
$[B{a^{ + + }}] = \frac{{{K_{sp}}}}{{[CO_3^ - ]}} = \frac{{5.1 \times {{10}^{ - 9}}}}{{1.0 \times {{10}^{ - 4}}}}$
$ = 5.1 \times {10^{ - 5}}\,M$
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$\Delta H_f^o[CO_2,g] = -394 \,kJ/mol$
$\Delta H_f^o[H_2O,l] = -286\, kJ/mol$
$\Delta H_f^o [propene ,g] = 20\,kJ/mol$
cyclopropane $(g)$ $\to$ propene $(g)$ ; $\Delta H^o_{isomerisation} = $ $-33\,kJ/mol$.
Calculate $\Delta H^o_{combustion}$ [cyclopropane, $(g)$]
......$ kJ/mol$
