MCQ
Solubility of $Ba{F_2}$ in a solution $Ba{(N{O_3})_2}$ will be represents by the concentration term
- A$[B{a^{ + 2}}]$
- B$[{F^ - }]$
- ✓$\frac{1}{2}[{F^ - }]$
- D$2\,[NO_3^ - ]$
The expression for the solubility product is given by,
$K _{ sp }=\left[ Ba ^{2+}\right]\left[ F ^{-}\right]^2$
The concentration of fluoride ions in the solution is as follows:
$\left[ F ^{-}\right]=2 s$
Thus, $s=\frac{1}{2}\left[ F ^{-}\right]$
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