MCQ
Solubility of $BaF_2$ in a solution of $Ba(NO_3)_2$ will be represented by the concentration term?
- A$[Ba^{+2}]$
- B$2[F^{\circleddash}]$
- ✓$\frac{1}{2}[F^{\circleddash}]$
- D$2[NO_3^{\circleddash}]$
✓
Answer
Correct option: C.
$\frac{1}{2}[F^{\circleddash}]$
c
$BaF _2 \longrightarrow \underset{s+x}{Ba _{( aq )}^{+2}}+\underset{(2s )}{2 F _{( aq) }^{-}}$
$BaF _2 \longrightarrow \underset{s+x}{Ba _{( aq )}^{+2}}+\underset{(2s )}{2 F _{( aq) }^{-}}$
$\underset{xM}{Ba \left( NO _{3 M }\right)_2} \longrightarrow \underset{x+s}{Ba _{( aq )}^{+2}}+2 NO _{3( aq )}^{-}$
Where $S =$ solubility of $BaF _2$
$\therefore \quad K _{ sp }=\left[ Ba ^{+2}\right]\left[ F ^{-}\right]^2$
$\therefore \quad\left[ F ^{-}\right]=\sqrt{\frac{ K _{ sp }}{\left[ Ba ^{+2}\right]}}$
$\therefore \quad$ Solubility of $BaF _2=\frac{1}{2} \times(2 s )$
$=\frac{1}{2} \times\left[ F ^{-}\right]$
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