MCQ
Solubility of calcium phosphate $($molecular mass $,M)$ in water is $\text{Wg}$ per $100mL$ at $25^\circ C$. Its solubility product at $25^\circ C$ will be approximately.
  • A
    $10^7\Big(\frac{\text{W}}{\text{M}}\Big)^3$
  • $10^7\Big(\frac{\text{W}}{\text{M}}\Big)^5$
  • C
    $10^5\Big(\frac{\text{W}}{\text{M}}\Big)^5$
  • D
    $10^3\Big(\frac{\text{W}}{\text{M}}\Big)^5$

Answer

Correct option: B.
$10^7\Big(\frac{\text{W}}{\text{M}}\Big)^5$
$\text{S}=\frac{10\text{W}}{\text{M}}\text{moL/ L}$
$\text{K}_{\text{sp}}$ of $\text{Ca}_3(\text{PO}_4)_2=108\text{S}^5$
$=108\Big(\frac{10\text{W}}{\text{M}}\Big)^5$
$=10^7\Big(\frac{\text{W}}{\text{M}}\Big)^5\ ($approximately.$)$

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