Solution of a linear inequality in variable x is represented on number line.
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$\text{x}\in[-\infty,5) $
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$\text{x}\in(-\infty,5) $
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$\text{x}\in(5,\infty) $
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$\text{x}\in[5,\infty) $
Solution of a linear inequality in variable x is represented on number line.
$\text{x}\in[-\infty,5) $
$\text{x}\in(-\infty,5) $
$\text{x}\in(5,\infty) $
$\text{x}\in[5,\infty) $
Solution:
The given graph represents all value of x greater than 5 including 5 on the real number line.
So, $\text{x}\in[5,\infty). $
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The equation of the line passing through the point (1, 2) and perpendicular to the line x + y + 1 = 0 is:
If the parabola y2 = 4ax passes through the point (3, 2), then the length of its latus rectum is:
$\frac{2}{3}$
$\frac{4}{3}$
$\frac{1}{3}$
$4$
The distance of the point of intersection of the lines 2x - 3y + 5 = 0 and 3x + 4y = 0 from the line 5x - 2y = 0 is:
$\frac{130}{17\sqrt{29}}$
$\frac{13}{7\sqrt{29}}$
$\frac{130}{7}$
If $\text{P}(\text{A}\cup\text{B})=\text{P}(\text{A}\cap\text{B})$ for any two events A and B, then:
$\text{P(A)}=\text{P(B)}$
$\text{P(A)}>\text{P(B)}$
$\text{P}(\text{A})<\text{P(B)}$
none of these.