If x < 5, then.
-
$-\text{x} < – 5 $
-
$-\text{x}\leq-5$
-
$-\text{x} > – 5 $
-
$-\text{x}\leq-5$
52 questions across 6 question groups — pick any mix to generate a MATHS paper with step-by-step answer keys.
M.C.Q (1 Marks)
11 Q→02True False[1 Marks ]
15 Q→03Fill In The Blanks[1 Marks ]
8 Q→042 Marks Questions
4 Q→053 Marks Question
6 Q→065 Marks Questions
8 Q→One sample from each question group in this chapter. Select any group above to see the full set with answer keys.
If x < 5, then.
$-\text{x} < – 5 $
$-\text{x}\leq-5$
$-\text{x} > – 5 $
$-\text{x}\leq-5$
If $|\text{x}+2|\leq9,$ then:
$\text{x}\in(-7,11)$
$\text{x}\in[-11, 7]$
$\text{x}\in[-\infty,-7)\cup(11,\infty) $
$\text{x}\in(-\infty,-7)\cup[11,\infty) $
If – 3x + 17 < – 13, then:
$\text{x}\in(10, \infty)$
$\text{x}\in[10, \infty)$
$\text{x}\in(-\infty\text{j},10]$
$\text{x}\in[-10, 10)$
Given that x, y and b are real numbers and x < y, b < 0, then:
$\frac{\text{x}}{\text{b}}<\frac{\text{y}}{\text{b}}$
$\frac{\text{x}}{\text{b}}\leq\frac{\text{y}}{\text{b}}$
$\frac{\text{x}}{\text{b}}>\frac{\text{y}}{\text{b}}$
$\frac{\text{x}}{\text{b}}\geq\frac{\text{y}}{\text{b}}$
If x is a real number and |x| < 3, then:
$\text{x}\geq3$
$-3<\text{x}<3$
$\text{x}\leq-3$
$-3\leq\text{x}\leq3$


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