MCQ
Solution of $ |\text{x}^2 – 10|\leq6$ is:
- A$\big(2, 4\big)$
- B$\big(– 4, – 2\big)$
- C$\big(– 4, – 2\big)\cup\big(2, 4\big)$
- D$\big[– 4, – 2\big]\cup\big[2, 4\big]$
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A(6, 3), B(-3, 5), C(4, -2) and D(x, 3x) are four points. If $\triangle\text{DBC} : \triangle\text{ABC}= 1 : 2,$ then x is equal to: