Question
Find the surface area of a cuboid whose:
Length $=2 m$, breadth $=4 m$ and height $=5 m$.

Answer

Length of cuboid $(1)=2 m$
$\text { Breadth }(b)=4 m$
$\text { Height }(h)=5 m$
$\therefore \text { Surface area }=2(1 \times b+b \times h+h \times l)$
$=2(2 \times 4+4 \times 5+5 \times 2) m^2$
$=2(8+20+10) m^2=76 m^2$

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