Question
Solve: $\frac{2\text{x}-(7-5\text{x})}{9\text{x}-(3+4\text{x})}=\frac{7}{6}$

Answer

$\frac{2\text{x}-(7-5\text{x})}{9\text{x}-(3+4\text{x})}=\frac{7}{6}$ $\Rightarrow\frac{2\text{x} - 7 + 5\text{x}}{9\text{x} - 3 - 4\text{x}} = \frac{7}{6}$ $\Rightarrow\frac{7\text{x} - 7}{5\text{x} - 3} = \frac{7}{6}$ $\Rightarrow6 (7\text{x} - 7) = 7 (5\text{x} - 3)$ (by cross multiplication) $\Rightarrow42\text{x} - 42 = 35\text{x} - 21$ $\Rightarrow 42\text{x} - 35\text{x} = 42 - 21$ $\Rightarrow7\text{x} = 21 $ $\Rightarrow\text{x}=\frac{21}{7}=3$ $\therefore \text{x} = 3$

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