MCQ
Solve $2\text{x}^2+\sqrt{2\text{x}+2}=0$
- A$\frac{-1\pm\text{i}\sqrt{7}}{2\sqrt{2}}$
- B$\frac{1\pm\text{i}\sqrt{7}}{2\sqrt{2}}$
- C$\frac{1\pm\sqrt{7}}{2\sqrt{2}}$
- D$\frac{-1\pm\sqrt{7}}{2\sqrt{2}}$
Solution:
$2\text{x}^2+\sqrt{2\text{x}+2}=0$
$\Rightarrow\text{D}=(\sqrt{2})^2-4.2.2=2-16=-14$
Since $\text{D}\leq0,$ imaginary roots are there.
$\Rightarrow\text{x}=\frac{-\sqrt{2\pm}\sqrt{\text{D}}}{2.2}=\frac{-\sqrt{2\pm\text{i}}\sqrt{\text{D}}}{2.2}=\frac{-1\pm\text{i}\sqrt{7}}{2\sqrt{2}}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Find the equation perpendicular to 2x - y = 4 and pass through (2, 4):
If $\text{f(x)}=\cos^2\text{x}+\sec^2\text{x},$ then:
$\text{f(x)}<1$
$\text{f(x)}=1$
$2<\text{f(x)}<1$
$\text{f(x)}\geq2$
[Hint: $\text{A.M}\geq\text{G.M.}$]