MCQ
Find the equation perpendicular to 2x - y = 4 and pass through (2, 4):
- A2x + y - 10 = 0
- Bx + 2y + 10 = 0
- Cx + 2y - 10 = 0
- Dx + y - 10 = 0
Find the equation perpendicular to 2x - y = 4 and pass through (2, 4):
Solution:
Line 2x - y = 4 has slope 2. Line perpendicular to given line has slope $\frac{-1}{2}$
equation is $(\text{y}-4) = \big(\frac{-1}{2}\big) (\text{x}-2)$
2y - 8 = -x + 2
⇒ x + 2y - 10 = 0
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