Question
Solve: $2x^4 – 5x^2 + 3 = 0$
✓
Answer
$2 x^4-5 x^2+3=0$
$\Rightarrow 2 x^4-3 x^2-2 x^2+3=0 $
$ \Rightarrow x^2\left(2 x^2-3\right)-1\left(2 x^2-3\right)=0$
$ \Rightarrow\left(2 x^2-3\right)\left(x^2-1\right)=0$
If $2 x^2-3=0$ or $x^2-1=0$
then $x^2=\frac{3}{2}$ or $x^2=1$
$\Rightarrow x= \pm \sqrt{\frac{3}{2}}$ or $x = \pm 1$
$\Rightarrow 2 x^4-3 x^2-2 x^2+3=0 $
$ \Rightarrow x^2\left(2 x^2-3\right)-1\left(2 x^2-3\right)=0$
$ \Rightarrow\left(2 x^2-3\right)\left(x^2-1\right)=0$
If $2 x^2-3=0$ or $x^2-1=0$
then $x^2=\frac{3}{2}$ or $x^2=1$
$\Rightarrow x= \pm \sqrt{\frac{3}{2}}$ or $x = \pm 1$
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