Solve: 3x + 8 >2, when x is a real number. - Vidyadip

Question

Solve: 3x + 8 >2, when x is a real number.

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Answer

It is given in the question that,
3x + 8 >2
$\Rightarrow$ 3x + 8 – 8 >2 – 8
$\Rightarrow$ 3x >- 6
$\Rightarrow$ $\frac{3 x}{3}>\frac{-6}{3}$
$\Rightarrow$ x > -2, where x is a real number.
It can be clearly observed that the solutions of 3x + 8 > 2 will be given by x > -2 which states that all the real numbers that are greater than -2.
$\therefore$ solution set = (-2, $\infty$)

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