Question
Solve:
$ a^4-1 / b^4 $

Answer

$ a^4-1 / b^4 $
$ =\left(a^2\right)^2-1 /\left(b^2\right)^2 $
$ =a^2-1 / b^2 a^2+1 / b^2 $
$ =a-1 / b a+1 / b a^2+1 / b^2 $

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