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Playing with Numbers — MATHS STD 8 — Question

Gujarat BoardEnglish MediumSTD 8MATHSPlaying with Numbers3 Marks
Question
Solve Cryptarithms. $\ \ \ \ \ \ \ \ \ \ \ \text{A}\ \ \ \ \text{B}\\\ \ \ \ \ \underline{+\ \ \ 3\ \ \ \ \ 7\ }\\\ \ \ \ \ {\ \ \ \ \ \ 9\ \ \ \ \text{A}\ }$
✓

Answer

Two possibilities of $A$ are:
$i.$ If $\text{B}+7<9,$
$\text{A}=6$
But clearly, if $A = 6,$
$\text{B}+7\geq9;$
It is impossible
$ii.$ If $\text{B}+7\geq9,$
$A = 5$ and $B + 7 = 5$
Clearly, $B = 8$
$\therefore A = 5, B = 8$

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