Question
Solve equation by factorization$x^2-(1+\sqrt{2}) x+\sqrt{2}=0$

Answer

$
\begin{aligned}
& x^2-(1+\sqrt{2}) x+\sqrt{2}=0 \\
& \Rightarrow x^2-x-\sqrt{2} x+\sqrt{2}=0 \\
& \Rightarrow(x-1)-\sqrt{2}(x-1)=0 \\
& \Rightarrow(x-1)(x-\sqrt{2})=0
\end{aligned}
$
Either $x-1=0$,
then $x=1$
or
$
x-\sqrt{2}=0 \text {, }
$
then $x =\sqrt{2}$
Hence $x=1, \sqrt{2}$.

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