Question
Solve for ' $\theta$ ': $\sec \left(\frac{\theta}{2}+10^{\circ}\right)=\frac{2}{\sqrt{3}}$

Answer

$ \sec \left(\frac{\theta}{2}+10^{\circ}\right)=\frac{2}{\sqrt{3}}$
$ \Rightarrow \sec \left(\frac{\theta}{2}+10^{\circ}\right)=\sec 30^{\circ}$
$ \Rightarrow \frac{\theta}{2}+10^{\circ}=30^{\circ}$
$ \Rightarrow \frac{\theta}{2}=20^{\circ}$
$ \Rightarrow \theta=40^{\circ} .$

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