Question
Solve for $x$ :
$\frac{1}{x+1}+\frac{3}{5 x+1}=\frac{5}{x+4}, x \neq-1,-\frac{1}{5},-4$

Answer


$\begin{array}{l}\frac{1}{x+1}+\frac{3}{5 x+1}=\frac{5}{x+4}, x \neq-1,-\frac{1}{5},-4 \\ \Rightarrow \frac{5 x+1+3 x+3}{(x+1)(5 x+1)}=\frac{5}{x+4} \\ \Rightarrow(x+4)(8 x+4)=5(x+1)(5 x+1) \\ \Rightarrow(x+4)(8 x+4)=5(x+1)(5 x+1) \\ \Rightarrow 8 x^2+32 x+4 x+16=5\left(5 x^2+x+5 x+1\right)\end{array}$
$\begin{array}{l}\Rightarrow 8 x^2+36 x+16=25 x^2+30 x+5 \\ \Rightarrow 17 x^2-6 x-11=0 \\ \Rightarrow 17 x^2-17 x+11 x-11=0 \\ \Rightarrow 17 x(x-1)+11(x-1)=0 \\ \Rightarrow(17 x+11)(x-1)=0 \\ \Rightarrow 17 x+11=0 \text { or } x-1=0 \\ \Rightarrow x=-\frac{11}{17} \text { or } x=1\end{array}$

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