Question
Solve for $x$ :
$\frac{1}{x+1}+\frac{3}{5 x+1}=\frac{5}{x+4}, x \neq-1,-\frac{1}{5},-4$
$\frac{1}{x+1}+\frac{3}{5 x+1}=\frac{5}{x+4}, x \neq-1,-\frac{1}{5},-4$
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Solve the given pair of linear equation by the elimination method and the substitution method: 3x + 4y = 10 and 2x – 2y = 2
| Class | $0-20$ | $20-40$ | $40-60$ | $60-80$ | $80-100$ |
| Frequency | $17$ | $f_1$ | $32$ | $f_2$ | $19$ |