Question
Solve for $x$ :
$\frac{2}{x+1}+\frac{3}{2(x-2)}=\frac{23}{5 x}, x \neq 0,-1,2$

Answer

Solving for $x$,
$\begin{array}{l}\Rightarrow \frac{2}{x+1}+\frac{3}{2(x-2)}=\frac{23}{5 x} \\\Rightarrow \frac{4(x-2)+3(x+1)}{2(x+1)(x-2)}=\frac{23}{5 x} \\\Rightarrow \frac{4 x-8+3 x+3}{2\left(x^2+x-2 x-2\right)}=\frac{23}{5 x} \\\Rightarrow \frac{7 x-5}{2\left(x^2-x-2\right)}=\frac{23}{5 x}\end{array}$
Cross multiplying both sides,
$\begin{array}{l}\Rightarrow 5 x(7 x-5)=46\left(x^2-x-2\right) \\\Rightarrow 35 x^2-25 x=46 x^2-46 x-92\end{array}$
Re-arranging the terms,
$\Rightarrow 11 x^2-21 x-92=0$
Solving the above quadratic equation by splitting the middle term,
$\begin{array}{l}\Rightarrow 11 x^2-44 x+23 x-92=0 \\\Rightarrow 11 x(x-4)+23(x-4)=0 \\\Rightarrow(11 x+23)(x-4)=0\end{array}$
Hence $x=4 \quad$ and $x=-\frac{23}{11}$

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