Question
Solve for $x , y :\left[\begin{array}{l}x^2 \\ y^2\end{array}\right]+2\left[\begin{array}{c}-2 x \\ -y\end{array}\right]=\left[\begin{array}{l}5 \\ 8\end{array}\right]$
✓
Answer
$x^2-4 x=5$
$y^2-2 y=8$
$y^2-2 y-8=0$
$(y-4)(y+2)=0$
$y=4,-2$
$x^2-4 x-5=0$
$(x-5)(x+1)=0$
$x=5,-1$
$x=-1,5 $ and $ y=4,-2$
$y^2-2 y=8$
$y^2-2 y-8=0$
$(y-4)(y+2)=0$
$y=4,-2$
$x^2-4 x-5=0$
$(x-5)(x+1)=0$
$x=5,-1$
$x=-1,5 $ and $ y=4,-2$
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