Question
Solve graphically : 2x + 3y ≤ 6 and x + 4y ≥ 4
✓
Answer
First we draw the lines AB and CD whose equations are 2x + 3y = 6 and x + 4y = 4 respectively.
The solution set of the given system of inequalities is shaded in the graph.
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$\text{x}=\frac{1-\text{t}^2}{1+\text{t}^2}\text{ and y}=\frac{2\text{t}}{1+\text{t}^2}$
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