Question
Solve graphically :3x + 2y ≥ 0

When x = 1, y = 1, then 3x + 2y = 3 + 2 = 5 which is greater than zero. ∴ 3x + 2y > 0 in this case. Hence (1, 1) lies in the required region. Therefore, the required region is the upper side which is shaded in the graph. This is the solution set of 3x + 2y ≥ 0.
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$\int_{-1}^1 \frac{x^3+2}{\sqrt{x^2+4}} \cdot d x$