Question
Solve : $\left|\frac{8-x}{2}\right|=5$
✓
Answer
$\left|\frac{8-x}{2}\right|=5$
$\therefore \quad \frac{8-x}{2}=5 \quad$ or $\quad \frac{8-x}{2}=-5$
$\therefore 8-x=10$ or $8-x=-10$. [Multiplying both the sides by 2 ]
$\therefore 8-10=x$ or $8+10=x$
$\therefore x=-2$ or $x=18$
$\therefore \quad \frac{8-x}{2}=5 \quad$ or $\quad \frac{8-x}{2}=-5$
$\therefore 8-x=10$ or $8-x=-10$. [Multiplying both the sides by 2 ]
$\therefore 8-10=x$ or $8+10=x$
$\therefore x=-2$ or $x=18$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
What will be the volume of a cube having length of edge 7.5 cm ?
Given: Length of edge of cube $(1)=7.5 cm$
To find: Volume of a cube
→Given: Length of edge of cube $(1)=7.5 cm$
To find: Volume of a cube
Draw a parallelogram PQRS. Draw diagonals PR and QS. Denote the intersection of diagonals by letter O. Compare the two parts of each diagonal with a divider. What do you find?
In $\triangle\text{ABC, }\angle\text {A}= \angle\text{B}=45^{\circ}.$ Which is its longest side?
→Find the median of the observations, 59, 75, 68, 70, 74, 75, 80.
In the adjoining figure, seg AB ≅ seg CB and seg AD ≅ seg CD. Prove that ∆ABD ≅ ∆CBD.
If $\frac{x}{y}=\frac{4}{5}$ then find the value of the ratio $\frac{4 x-y}{4 x+y}$.
→Explain the meaning of the following terms:
True class limits.
True class limits.
Using opposite angles test for parallelogram, prove that every rectangle is a parallelogram.
Given:
□ABCD is a rectangle.
To prove: Rectangle ABCD is a parallelogram.
Factorise:
$(x+2)^3+(x-2)^3$
→$(x+2)^3+(x-2)^3$
If $10^x=64$, find the value of $10^{\left(\frac{x}{2}+1\right)}$.
→