Question
Solve quadratic equation using formula : x² - 2x - 3 = 0

Answer


$\begin{array}{l}\text { comparing with } a x^2+b x+c=0 \\ \text { we get } a=1, b=-2, c=-3 \text {, } \\ \therefore b^2-4 a c=(-2)^2-4 \times 1 \times(-3)=4+12=16 \\ \therefore x=\frac{-(-2)+\sqrt{16}}{2} \text { or } x=\frac{-(-2)-\sqrt{16}}{2} \\ =\frac{2+4}{2} \text { or } \frac{2-4}{2} \\ =3 \text { or }-1\end{array}$

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