Gujarat BoardEnglish MediumSTD 12 ScienceMathsDifferential Equations4 Marks
Question
Solve the differential equation$(\text{y}+3\text{x}^2)\frac{\text{dx}}{\text{dy}}=\text{x}$
✓
Answer
We have, $(\text{y}+3\text{x}^2)\frac{\text{dx}}{\text{dy}}=\text{x}$ $\Rightarrow\frac{\text{dy}}{\text{dy}}=\frac{\text{y}+3{\text{x}^{\text{2}}}}{\text{x}}$ $\Rightarrow\frac{\text{dy}}{\text{dx}}-\frac{1}{\text{x}}{\text{y}}=3{\text{x}}\ ...(1)$ Clearly, it is a linear differential equation of the form $\frac{\text{dy}}{\text{dx}}+\text{Py}=\text{Q}$ Where $\text{P}=-\frac{1}{\text{x}}$ and $\text{Q}=3\text{x}$ $\therefore \ \text{I}.\text{F}. = \text{e}^{\int{\text{P}\text{dx}}}$ $ =\text{e}^{-\int\frac{1}{\text{x}}\text{dx}}$ $=\text{e}^{-\log\text{x}}$ $=\frac{1}{\text{x}}$ Multiplying both sides of (1) by $\text{I.F.}=\frac{1}{\text{x}},$ we get $\frac{1}{\text{x}}\Big(\frac{\text{dy}}{\text{dx}}-\frac{1}{\text{x}}{\text{y}}\Big)=\frac{1}{\text{x}}3\text{x}$ $\Rightarrow\frac{1}{\text{x}}\frac{\text{dy}}{\text{dx}}-\frac{1}{\text{x}^{2}}\text{y}=3$ Integrating both sides with respect to x, we get $\frac{1}{\text{x}}\text{y}=3\int\text{dx}+\text{C}$ $\Rightarrow\frac{\text{y}}{\text{x}}=3\text{x}+\text{C}$ Hence, $\frac{\text{y}}{\text{x}}=3\text{x}+\text{C}$ is the required solution.
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