Question
Solve the division: $-20x^4$ $\div$ $10x62$

Answer

Now, $-20 \mathrm{x}^4=-2 \times 2 \times 5 \times \mathrm{x} \times \mathrm{x} \times \mathrm{x} \times \mathrm{x}$
and $10 \mathrm{x}^2=2 \times 5 \times \mathrm{x} \times \mathrm{x}$
Therefore, $(–20x^4)$ $\div$ $10x^2=$ $\frac{-2\times2\times5\times x\times x\times x\times x}{2\times5 \times x\times x}$
$ = -2$ $\times$ x $\times$ $x = -2x^2$

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