Question
Solve the equation and check your result: $4z + 3 = 6 + 2z$

Answer

$4z + 3 = 6 + 2z$
$4z – 2z = 6 – 3 ... [$Transposing $2z$ to $L.H.S.$ and $3$ to $R.H.S]$
$\therefore 2z = 3$
$\therefore z = \frac{3}{2} ... [$Dividing both sides by $2]$
This is the required solution.
Verification,
$L.H.S = 4\left( {\frac{3}{2}} \right) + 3 = 6 + 3 = 9$
$R.H.S = 6 + 2z = 6 + 2\left( {\frac{3}{2}} \right) = 6 + 3 = 9$
Therefore, $L.H.S = R.H.S$

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