Question
Solve the following differential equation
$\frac{\text{dy}}{\text{dx}}=(\text{e}^\text{x}+1)\text{y}$

Answer

 We have

$\frac{\text{dy}}{\text{dx}}=(\text{e}^\text{x}+1)\text{y}$

$\Rightarrow\frac{1}{\text{y}}\text{dy}=(\text{e}^\text{x}+1)\text{dx}$

Integrating both sides, we get

$\frac{1}{\text{y}}\text{dy}=(\text{e}^\text{x}+1)\text{dx}$

$\Rightarrow\log|\text{y}|=\text{e}^\text{x}+\text{x} +\text{C}$

Hence,
 $\Rightarrow\log|\text{y}|=\text{e}^\text{x}+\text{x} +\text{C}$ is the required solution. 

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