Question
Solve the following differential equations:
$\tan\text{y dx}+\sec^2\text{y}\tan\text{x dy}=0$
$\tan\text{y dx}+\sec^2\text{y}\tan\text{x dy}=0$
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$\cos\text{x}\cos\text{y}\frac{\text{dy}}{\text{dx}}=-\sin\text{x}\sin\text{y}$
| | A | B |
| Grinding | 1 | 2 |
| Turning | 3 | 1 |
| Assembling | 6 | 3 |
| Testing | 5 | 4 |