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Linear Equations in one variable — Maths STD 6 — Question

Maharashtra BoardEnglish MediumSTD 6MathsLinear Equations in one variable4 Marks
Question
Solve the following equation and verify the answer:
3(2 - 5x) - 2(1 - 6x) = 1
✓

Answer

3(2 - 5x) - 2(1 - 6x) = 1 ⇒ 6 - 15x - 2 + 12x = 1 (Removing brackets) ⇒ 6 - 2 - 15x + 12x = 1 ⇒ 4 - 3x = 1 -3x = 1 - 4 (Transposing 4 to R.H.S.) ⇒ -3x = -3$\Rightarrow\frac{\text{-3x}}{-3}=\frac{-3}{-3}$
(Dividing both sides by -3) ⇒ x = 1 So, x = 1 is a solution of the given equation. Check: Substituting x = 1 in the given equation, we get L.H.S. = 3(2 - 5 × 1) - 2(1- 6 × 1) = 3(2 - 5) - 2(1 - 6) = [3 × (-3)] + [-2 × (-5)] = -9 + 10 = 1 = R.H.S. $\therefore$ When x = 1, we have L.H.S. = R.H.S.

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