Question
Solve the following equation and verify the answer: $x - 7 = 6$

Answer

$x - 7 = 6$ Adding $7$ on both the sides:
$\Rightarrow x - 7 + 7 = 6 + 7 $
$\Rightarrow x = 13$
Verification: Substituting $x = 13$ in the $L.H.S. $
$\Rightarrow 13 - 7 = 6 = R.H.S. $
$L.H.S. = R.H.S$. Hence, verified.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Simplity the following to its lowest term: $\frac{150}{50}$
The $L.C.M$ and $H.C.F$ of two numbers are $180$ and $6$ respectively. If ones of the numbers is $30$, find the other number.
Arrange the fractions $\frac23,\frac34,\frac12$ and $\frac56$ in ascending order.
State the type of the following angles:
A train takes $2$ hours to travel from Ajmer to Jaipur, which are $130\ km$ apart. How much time will it take to travel from Delhi to Bhopal which are $780\ km$ apart, if the train is travelling at the uniform speed?
Draw a rectangle of size 12 units × 8 units. Draw another rectangle inside it, without touching the outer rectangle that occupies exactly half the area.
Adjacent figure is a vertical number line, representing an integer. Observe it and locate the points:
Is point G a negative integer or a positive integer?
Split the shape into a rectangle and find its area. (The measures are given in centimetres)
The following data gives the number of students of Delhi city who went abroad for study during some years:
Image
Represent the above data with the help of a bar graph. ,
(a) Which year maximum students went to study abroad from Delhi.
(b) Which year minimum students went to study abroad from Delhi.
(c) How may total students went abroad to study between 2015 and 2017 including both the year.
(d) How may total students went abroad to study between 2014 and 2018 including both the year.
If B is the mid point of $\overline{A C}$ and $C$ is the point of $\overline{\mathrm{BD}}$ . where $A, B, C, D$ lie on a straight line, say why $AB = CD?$