Question
Solve the following equation by trial and error method:
$\frac{1}{2}\text{x}+7=11$
$\frac{1}{2}\text{x}+7=11$
✓
Answer
The given equation is $\frac{1}{2}\text{x}+7=11$ We guess and try several values of x to find L.H.S. and R.H.S. and stop when L.H.S. = R.H.S.
When x = 8, we have L.H.S. = R.H.S So, x = 8 is the solution of the given equation.
| x | L.H.S. | R.H.S. |
| 2 | $\frac{1}{2}\times2+7=8$ | 11 |
| 4 | $\frac{1}{2}\times4+7=9$ | 11 |
| 6 | $\frac{1}{2}\times6+7=10$ | 11 |
| 8 | $\frac{1}{2}\times8+7=11$ | 11 |
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