Algebraic Expressions and Operations on them — Maths STD 7 — Question

\begin{array}{ll}
& 4 x+\frac{1}{2}=\frac{9}{2} \\
\therefore & 4 x=\frac{9}{2}-\frac{1}{2} \\
\therefore & 4 x=\frac{8}{2} \\
\therefore & 4 x=4 \\
\therefore & x=\frac{4}{4} \\
\therefore & x=1
\end{array}