Question
Solve the following equations :
$5 t-3=3 t-5$

Answer

We have,
$5 t-3=3 t-5$
$\Rightarrow \quad 5 t-3 t=-5+3\quad$ [transposing 3t to LHS and -3 to RHS]
$\Rightarrow \quad 2 t=-2$
$\Rightarrow \quad t=\frac{-2}{2} \quad$ [dividing both sides by 2]
$\therefore t=-1$, which is the required solution.
Check For $t=-1$
LHS $=5(-1)-3=-5-3=-8$
RHS $=3(-1)-5=-3-5=-8$
$\therefore \quad LHS = RHS \quad$ [as required]

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free