Question
Evaluate:$\Big(\frac{4}{7}\Big)^3$

Answer

$\Big(\frac{4}{7}\Big)^3$$=\Big(\frac{4}{7}\times\frac{4}{7}\times\frac{4}{7}\Big)$
$=\Big(\frac{64}{343}\Big)$
Thus, the cube of $\Big(\frac{4}{7}\Big)$ is $\Big(\frac{64}{343}\Big)$

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