Question
Solve the following equations. Check your result in case.
$8x - 3 = 9 - 2x$
$8x - 3 = 9 - 2x$
✓
Answer
$8\text{x}-3=9-2\text{x}$
$\Rightarrow8\text{x}+2\text{x}=9+3$ (By transposing)
$\Rightarrow10\text{x}=12$
$\Rightarrow\text{x}=\frac{12}{10}=\frac{6}{5}$
$\therefore\text{x}=\frac{6}{5}$
Check:
$\text{L.H.S}=8\text{x}-3=8\times\frac{6}{5}-3$
$=\frac{48}{5}-\frac{3}{1}=\frac{48-15}{5}=\frac{33}{5}$
$\text{R.H.S}=9-2\text{x}$
$=9-2\times\frac{6}{5}=\frac{9}{1}-\frac{12}{5}$
$=\frac{45-12}{5}=\frac{33}{5}$
$\therefore\text{L.H.S}=\text{R.H.S}$
Hence $\text{x}=\frac{6}{5}$
$\Rightarrow8\text{x}+2\text{x}=9+3$ (By transposing)
$\Rightarrow10\text{x}=12$
$\Rightarrow\text{x}=\frac{12}{10}=\frac{6}{5}$
$\therefore\text{x}=\frac{6}{5}$
Check:
$\text{L.H.S}=8\text{x}-3=8\times\frac{6}{5}-3$
$=\frac{48}{5}-\frac{3}{1}=\frac{48-15}{5}=\frac{33}{5}$
$\text{R.H.S}=9-2\text{x}$
$=9-2\times\frac{6}{5}=\frac{9}{1}-\frac{12}{5}$
$=\frac{45-12}{5}=\frac{33}{5}$
$\therefore\text{L.H.S}=\text{R.H.S}$
Hence $\text{x}=\frac{6}{5}$
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