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Exponents Of Real Numbers — Maths STD 9 — Question

Gujarat BoardEnglish MediumSTD 9MathsExponents Of Real Numbers2 Marks
Question
Solve the following equations for x: $7^{2\text{x}+3}=1$
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Answer

We have,$\Rightarrow7^{2\text{x}+3}=1$
$\Rightarrow7^{2\text{x}+3}=7^0$
$\Rightarrow2\text{x}+3=0$
$\Rightarrow2\text{x}=-3$
$\Rightarrow​​\text{x}=-\frac{3}{2}$

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