Question
Solve the following quadratic equation:(2x - 3)(3x + 1) = 0
✓
Answer
(2x - 3)(3x + 1) = 0⇒ 2x - 3 = 0 or 3x + 1 = 0
⇒ 2x = 3 or 3x = -1
$\Rightarrow\text{x}=\frac{3}{2}$ or $\text{x}=-\frac{1}{3}$
⇒ 2x = 3 or 3x = -1
$\Rightarrow\text{x}=\frac{3}{2}$ or $\text{x}=-\frac{1}{3}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Solve the following quadratic equation for: $4 \sqrt{3} x^2+5 x-2 \sqrt{3}=0$
→Which value(s) of $\lambda,$ do the pair of linear equations $\lambda\text{x}+\text{y}=\lambda^2$ and $\text{x}+\lambda\text{y}=1$have:
Infinitely many solutions?
→Infinitely many solutions?
What is the angle of elevation of the Sun when the length of the shadow of a vetical pole is equal to its height?
Prove that $2+3 \sqrt{3}$ is an irrational number. It is given that $\sqrt{3}$ is an irrational number.
→From a circular piece of cardboard of radius 3cm two sectors of 90° have been cut off. Find the perimeter of the remaining portion nearest hundredth centimeters $\Big(\text{Take }\pi =\frac{22}{7}\Big). $
→If $\sin (A+B)=1$ and $\cos (A-B)=1$, find $A$ and $B$.
→Which of the following are quadratic equations?
$3x^2 - 5x + 9 = x^2 - 7x + 3$
→$3x^2 - 5x + 9 = x^2 - 7x + 3$
If $3 \tan \theta=4$, evaluate $\frac{3 \sin \theta+2 \cos \theta}{3 \sin \theta-2 \cos \theta}$.
→In the given figure, if $AD \bot BC$, prove that $AB^2 + CD^2 = BD^2 + AC^2.$
→$\sin ( A + B )=1\ \&\ \sin (A- B )=\frac{1}{2}$,$0 \leq A + B =90^{\circ}\ \&\ A> B$, then find $A\ \&\ B$.
→