Question
Solve the following quadratic equation:$3x^2 - 2x - 1 = 0$
✓
Answer
$3x^2 - 2x - 1 = 0$
$\Rightarrow 3x^2 - 3x + 1x - 1 = 0$
$\Rightarrow 3x(x - 1) + 1(x - 1) = 0$
$\Rightarrow (x - 1)(3x + 1) = 0$
$\Rightarrow x - 1 = 0$ or $3x + 1 = 0$
$\Rightarrow x = 1$ or $\text{x}=\frac{-1}{3}$
Hence, $1$ and $\frac{-1}{3}$ are the roots of the equation $3x^2 - 2x - 1 = 0$
$\Rightarrow 3x^2 - 3x + 1x - 1 = 0$
$\Rightarrow 3x(x - 1) + 1(x - 1) = 0$
$\Rightarrow (x - 1)(3x + 1) = 0$
$\Rightarrow x - 1 = 0$ or $3x + 1 = 0$
$\Rightarrow x = 1$ or $\text{x}=\frac{-1}{3}$
Hence, $1$ and $\frac{-1}{3}$ are the roots of the equation $3x^2 - 2x - 1 = 0$
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