Question
Solve the following quadratic equation:$9x^2 - 3x - 2 = 0$
✓
Answer
$9x^2 - 3x - 2 = 0$
$\Rightarrow 9x^2 - 6x + 3x - 2 = 0$
$\Rightarrow 3x(3x - 2) + 1(3x - 2) = 0$
$\Rightarrow (3x - 2)(3x + 1) = 0$
$\Rightarrow 3x - 2 = 0$ or $3x + 1 = 0$
$\Rightarrow\text{x}=\frac{2}{3}$ or $\text{x}=-\frac{1}3{}$
$\Rightarrow 9x^2 - 6x + 3x - 2 = 0$
$\Rightarrow 3x(3x - 2) + 1(3x - 2) = 0$
$\Rightarrow (3x - 2)(3x + 1) = 0$
$\Rightarrow 3x - 2 = 0$ or $3x + 1 = 0$
$\Rightarrow\text{x}=\frac{2}{3}$ or $\text{x}=-\frac{1}3{}$
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