Question
Two coines are tossed simultaneously. Find the probability of getting exactly one head.
✓
Answer
$\because$ Two coins are tossed
$\therefore$ Possible outcome will be (HH, HT, TH, TT)
Total = 4
$\therefore$ Actually outcomes will be HT, TH = 2
$\therefore\ \text{P(E)}=\frac{\text{No. of actual outcomes}}{\text{No. of possible outcomes}}=\frac{2}{4}=\frac{1}{2}$
$\therefore$ Possible outcome will be (HH, HT, TH, TT)
Total = 4
$\therefore$ Actually outcomes will be HT, TH = 2
$\therefore\ \text{P(E)}=\frac{\text{No. of actual outcomes}}{\text{No. of possible outcomes}}=\frac{2}{4}=\frac{1}{2}$
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