Question
Solve the following quadratic equation by completing the square method.
$9 y^2-12 y+2=0$
$9 y^2-12 y+2=0$
✓
Answer
$9y^2-12y + 2 =0$
$(3 y)^2-2 \times 3 y \times 4+(4)^2-(4)^2+2=0$
$(3 y)^2-2 \times 3 y \times 4+(4)^2-16+2=0$
$(3 y-4)^2-14=0$
$(3 y-4)^2=14$
$3 y-14= \pm \sqrt{ } 14$
$3 y=14 \pm \sqrt{ } 14$
$y=(14 \pm \sqrt{ } 14) / 3$
$(3 y)^2-2 \times 3 y \times 4+(4)^2-(4)^2+2=0$
$(3 y)^2-2 \times 3 y \times 4+(4)^2-16+2=0$
$(3 y-4)^2-14=0$
$(3 y-4)^2=14$
$3 y-14= \pm \sqrt{ } 14$
$3 y=14 \pm \sqrt{ } 14$
$y=(14 \pm \sqrt{ } 14) / 3$
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