Question
Solve the following quadratic equation by factorization.
2y2 + 27y + 13 = 0
2y2 + 27y + 13 = 0
✓
Answer
$\begin{array}{l}
2 y^2+27 y+13=0 \\
\Rightarrow 2 y^2+26 y+y+13=0 \\
\Rightarrow 2 y(y+13)+(y+13)=0 \\
\Rightarrow(2 y+1)(y+13)=0 \\
2 y+1=0 \Rightarrow 2 y=-1 \Rightarrow y=-\frac{1}{2} \\
y+13=0 \Rightarrow y=-13
\end{array}$
Hence, ${ }^y=-13$ and $y=-\frac{1}{2}$ are roots of the equation.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Solve the following simultaneous equations:
$x+y=3$; $3x-2y=4$
→$x+y=3$; $3x-2y=4$
Find the value of p for which the numbers 2p - 1, 3p + 1, 11 are in AP.
Hence, find the numbers.
Hence, find the numbers.
Determine nature of roots of the quadratic equations : x² + 2x - 9 = 0
Define HCF of two positive integers and find the HCF of the following pairs of numbers:
240 and 6552
240 and 6552
Using prime factorization, find the HCF and LCM of:
17, 23, 29
17, 23, 29
In the given figure, the chord AB of the larger of the two concentric circles, with centre O, touches the smaller circle at C. Prove that AC = CB.
Solve the following quadratic equation by factorization.
$5 m^2=22 m+15$
→$5 m^2=22 m+15$
What must be subtracted from the polynomial $f(x) = x^4 + 2x^3 − 13x^2 − 12x + 21$ so that the resulting polynomial is exactly divisible by $x^2 − 4x + 3$?
→For the equation ? + 2? = 19 and 2? − 3? = − 3 Find the value of D
In the following figure, from a rectangular region $A B C D$ with $A B=20 cm$, a right triangle $A E D$ with $A E=9 cm$ and $D E$ $=12 cm$, is cut off.
On the other end, taking BC as diameter, a semicircle is added on outside' the region. Find the area of the shaded region. [Use $\pi=\frac{22}{7}$ ]
→On the other end, taking BC as diameter, a semicircle is added on outside' the region. Find the area of the shaded region. [Use $\pi=\frac{22}{7}$ ]